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13 February, 16:53

Find the zeroes of the function algebraically. write the answer, if applicable, in fraction form. ƒ (x) = 2x2 - 3x - 20

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  1. 13 February, 19:51
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    First let's factorise the function:

    f (x) = 2x^2 - 3x - 20

    = (2x + 5) (x - 4)

    Now make f (x) = 0:

    0 = (2x + 5) (x - 4)

    x = - 5/2 or x = 4
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