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6 October, 05:44

The surface areas of two similar solids are 384 yd2 and 1057 yd2. the volume of the larger solid is 1795 yd3. what is the volume of the smaller solid?

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  1. 6 October, 08:58
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    For similar triangles, the ratio of the corresponding sides are equal. To determine the common ratio, we take the square root of the ratio of the given areas.

    ratio = sqrt (384 / 1057)

    ratio = 384/1057

    Then, for the volume, we have to cube the ratio calculated above. If we let x be the value of the volume of the smaller solid.

    (384/1057) ^3 = x/1795

    x = 86 yd

    Thus, the volume of the smaller figure is 86 yd³.
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