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13 November, 13:11

A restaurant is at 75% cpacity with 120 patrons. How many people would be in the restaurants at 100% capacity?

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Answers (2)
  1. 13 November, 15:59
    0
    75%=120

    1%=120/75

    100% = 1% x 100

    100% = (120/75) x100

    100% = 160
  2. 13 November, 16:13
    0
    160 patrons would be the 100% capacity
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