What interval includes all possible values of x, where - 3 (6 - 2x) ≥ 4x + 12?

Well, we need to solve the inequality in terms of x ...

-3 (6-2x) ≥4x+12 carry out indicated multiplication on left side

-18+6x≥4x+12 subtract 4x from both sides

-18+2x≥12 add 18 to both sides

2x≥30 divide both sides by 2

x≥15, in interval notation:

x=[15, + oo)