Which equation is equivalent to log4 + log (x + 2) = 1?

x - 2 = 101

4x + 8 = 101

4x + 8 = 1

4/x+2=10^1

We have the following expression:

log4 + log (x + 2) = 1

By properties of logarithm we can rewrite the expression as:

log (4 * (x + 2)) = 1

Then, Rewriting we have:

10 ^ (log (4 * (x + 2))) = 10 ^ 1

4 * (x + 2) = 10 ^ 1

Rewriting:

4x + 8 = 10 ^ 1

Answer:

The equivalent expression is:

4x + 8 = 10 ^ 1