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28 November, 00:06

What values of c and d make the equation true? Assume and

c = 1, d = 3

c = 1, d = 32

c = 2, d = 8

c = 2, d = 32

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Answers (1)
  1. 28 November, 02:53
    0
    The equation for this problem is

    ∛ (162 x^c y⁵) = 3x²y ∛ (6y^d)

    First, we take the cube of the two sides of the equation

    162 x^c y⁵ = 27 x⁶ y³ (6 y^d)

    Simplifying

    x^c y⁵ = x⁶ y^ (3 + d)

    x^c

    Next, equate the exponents

    For x:

    c = 2

    For y:

    5 = - 3 + d

    d = 8

    The answer is

    c = 2 and d = 8
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