John has 14 coins that have a total of $2.30. the coins are nickels and quarters. which system of equations can be used to find the answer to how many of each coin john has?

Total coins = 14

n = # of nickels,.05n = amount of $ in nickels

q = # of quarters,.25q = amount of $ in quarters

So the following 2 equations can be used to solve this system:

1).05n +.25q = 2.30

2) n + q = 14

I'm going to use the elimination method, choosing to eliminate the q, so I need a -.25q to cancel out the other +.25q:

-.25 (n + q = 14)

-.25n -.25q = - 3.5

+.05n +.25q = 2.30

-.20n = - 1.2

-.20n/-.20 = - 1.2/-.20

n = 6

n + q = 14

q = 14-n = 14-6 = 8

Therefore John has 6 nickels and 8 quarters!