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14 December, 02:52

What is the solution to the equation below? log64x^2-log6x=2

x=1/2

x=3/2

x=3

x=9

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Answers (1)
  1. 14 December, 05:44
    0
    First, we need to put the conditions: 4x^2 >0 which is obviously true

    x>0

    We will apply the formulas:

    loga (x) - loga (y) = loga (x/y)

    and

    if loga (x) = b then x = a^b

    log6 (4x^2) - log6 (x) = 2

    Applying first formula

    log6 (4x^2/x) = 2

    log6 (4x) = 2

    Applying the second formula:

    4x = 36

    x=9
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