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19 November, 19:46

Which of the following tables shows the correct steps to transform x^2+6x + 8=0

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  1. 19 November, 22:22
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    Perhaps the most concise way to factor is by "completing the square" which is how the quadratic formula is derived ...

    x^2+6x+8=0 move constant to other side, subtract 8 from both sides

    x^2+6x=-8, halve the linear coefficient, square it, then add that to both sides, in this case (6/2) ^2=3^2=9

    x^2+6x+9=1 now the left side is a perfect square of the form

    (x+3) ^2=1 take the square root of both sides

    x+3=±√1 subtract 3 from both sides

    x=-3±√1

    x=-3±1

    x=-4 and - 2

    Since the zeros occur when x=-4 and - 2 the factors of the equation are:

    (x+2) (x+4)
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