Find the axis of symmetry for y=3x^2-6x-4

In the quadratic equation y = ax² + bx + c, the axis of symmetry can be determined with

x = - b/2a

Solution:

Identify the coefficient of the quadratic equation y = 3x² - 6x - 4

a = 3

b = - 6

c = - 4

The axis symmetry will be

x = - b / 2a

x = - (-6) / 2 (3)

x = 6/6

x = 1

The axis of symmetry is x = 1