An artist drew a rectangle. the artist then modified the rectangle so thatthe length ofthe rectawngle increased by 30 percent and the width of the rectangle decreased by 40 percent. after the modification, what was the percent decrease in the area of the rectangle?

Question

Mathematics

Cullen Riley

8 January, 13:30

An artist drew a rectangle. the artist then modified the rectangle so thatthe length ofthe rectawngle increased by 30 percent and the width of the rectangle decreased by 40 percent. after the modification, what was the percent decrease in the area of the rectangle?

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Todd Fernandez · Answer 1

The dimensions of the original rectangle

length - L

width - W

area = L*W = LW

after the modification, new dimensions are

length increased by 30 %

Length = L * 1.3 = 1.3L

Width = W * 0.6 = 0.6W

new area = 1.3L * 0.6W

= 0.78LW

the percent decrease in area

decrease % = (difference in area) / original area * 100

= (LW - 0.78LW) / LW * 100

= 0.22LW/LW * 100

= 22%

percent decrease is 22%