A region is bounded in the second quadrant by the curve y=ln (1-x), the line y=3, and the y-axis. Find the area of the region.

Would the interval be 3 and 0 and would the equation be set up like 3-ln (1-x) upper bound 3 and lower bound 0?

Question

Jaiden Flynn

24 March, 11:48

+4

Answers (1)

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Kianna Lang · Answer 1

Yes that's right, the intervals would be 3 and 0, and 3-ln (1-x) upper bound 3 and lower bound 0. Exactly.

A region is bounded in the second quadrant by the curve y=ln (1-x), the line y=3, and the y-axis. Find the area of the region.Would the interval be 3 and 0 and would the equation be set up like 3-ln (1-x) upper bound 3 and lower bound 0?