The sum of four consecutive whole numbers is 230. Find the numbers.

х is the first number

(x + 1) is the second number

(x + 2) is the third number

(x + 3) is the fourth number

x + x+1 + x+2 + x+3 = 230

4x + 6 = 230

4x = 230 - 6

4x = 224

x = 224/4

x = 56 the first number

56 + 1 = 57 the second number

56 + 2 = 58 the third number

56 + 3 = 59 the fourth number

Answer: 56, 57, 58, 59.

X + x + 1 + x + 2 + x + 3 = 230

4x + 6 = 230

4x = 224

x = 56

The numbers are 56, 57, 58 and 59.