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16 December, 21:33

The area of a rectangular classroom is given by the trinomial a - 4a - 21. The length of the rectangle is a+3. What is the expression for the width of the classroom?

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  1. 17 December, 01:18
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    I am assuming you wrote the problem wrong. Is it a^2?

    A^2 - 4A-21=0

    (A-7) (A+3) = 0

    A=7 A=-3, ignore the negative number because it doesn't make sense if you plug in for a.

    length=a+3=7+3=10

    Width=7=a
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