Y = x2 + 3x - 10

For the above quadratic equation find:

a. The y-intercept.

b. The x-intercepts if possible.

c. The vertex.

d. The line of symmetry.

Note: y = x2 + 3x - 10 should be y = x^2 + 3x - 10, where " ^ " indicates exponentiation.

To find the y-int.: Let x = 0 and find y. That intercept is (0, - 10).

To find the x-int.: Set y = x^2 + 3x - 10 = to 0, and solve for x. You could, for example, use the quadratic formula, completing the square, graphing, factoring, etc. x^2 + 3x - 10 = 0 can be factored easily:

(x+5) (x-2) = 0, so that x = - 5 and x=2. The x-int. are (-5,0) and (2,0).

The x-coord. of the vertex can be found by using the formula x = - b / (2a).

Once you have that, subst. that result into the given formula and calculate y.

The line of symm. has precisely the same form: x = - b / (2a), where

b=3 and a = 1. Here we don't need or care about c = - 10.