What is the question? compare: 17,643251; 17633512; and 17633893

Hello,

All numbers are integers.

The number having the most number of digits is the greater.

But we are not lucky they have all 8 digits.

We must begin to compare the left most digit

Let's call p the position from left of the digit we examine.

We call x1, x2, x3 the numbers.

p=1: n1 (p) = 1; n2 (p) = 1; n3 (p) = 1 : we must go further

p=2: n1 (p) = 7; n2 (p) = 7; n3 (p) = 7 : we must go further

p=3: n1 (p) = 6; n2 (p) = 6; n3 (p) = 6 : we must go further

p=4: n1 (p) = 4; n2 (p) = 3; n3 (p) = 3 : so n1 is the greater but we must go further

p=5: n2 (p) = 3; n3 (p) = 3 : we must go further

p=6: n2 (p) = 5; n3 (p) = 8 : n2 is the median, and n3 the smallest

so n2
or 17633512<17633893< 17,643251

I have explain as i were a cumputer.