Find the solutions

x^2=16x-28

Minus 16x both sides and add 28 to both sides

x^2-16x+28=0

factor

hmm, what 2 numbers multiply to 28 and add to - 16

hmm

1 and 28? nope

2 and 14? yep

since middle term is negative and last tem is positive, both of the factors are negative

(x-14) (x-2) = 0

set each to zero

x-14=0

x=14

x-2=0

x=2

x=2 and 14