Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 38 feet

Question

Mathematics

Jamiya Marshall

31 May, 02:14

Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 38 feet

+3

Answers (1)

Know the Answer?

Jamari Wiggins · Answer 1

P = 2 (L + W)

P = 38

L = 2W + 1

38 = 2 (2W + 1 + W)

38 = 2 (3W + 1)

38 = 6W + 2

38 - 2 = 6W

36 = 6W

36/6 = W

6 = W < = = = width

L = 2W + 1

L = 2 (6) + 1

L = 12 + 1

L = 13 < = = = length