At noon, ship a is 50 km west of ship

b. ship a is sailing south at 10 km/h and ship b is sailing north at 20 km/h. how fast is the distance between the ships changing at 4:00 pm? (round your answer to one decimal place.) 23.05 incorrect: your answer is incorrect. km/h

Given: dA/dt=10 km/hr and dB/dt=20 km/hr

bade of the triangle is 50 km

we are required to find dD/dt when t=4 hr

(A+B) ^2+50^2=D^2

d/dt ((A+B) ^2+50^2) = d/dt (D^2)

[d (A+B) ]/dt2 (A+B) (2) = dD/dt2D

A=10km/hr*4hr=40 km

B=20km/hr*4hr=80 km

(10+20) * (2) * (120) * (2) = 2*√8000*dD/dt

dD/dt=7200/sqrt (8000)

80.5 km/hr