Write (3i-2/3) - (6i-5) as a complex number in standard form

The correct answer is B. 13/3 - 3i

The standard form of a complex number is: a+bi

thus evaluating the expression we get:

(3i-2/3) - (6i-5)

opening the parenthesis we get:

3i-2/3-6i+5

= (3i-6i) - 2/3+5

=-3i+13/3

thus the standard form will be:

13/3-3i

multiplying through by 3 we get:

13-9i