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19 October, 12:01

Suppose that people's heights (in centimeters) are normally distributed with a mean of 170 and a standard deviation of 5. We find the heights of 50 people.

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  1. 19 October, 14:40
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    We have

    mean=mu=170

    standard deviation=sigma=5

    can now calculate the Zmin and Zmax using Z = (X-mean) / standard deviation

    Zmin = (165-170) / 5=-1

    Zmax = (175-170) / 5=+1

    From normal probability tables,

    P (z
    P (z
    P (165
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