A set of 48 cards is numbered with positive integers from 1 to 48.

If the cards are shuffled and one is chosen at random, what is the probability that the number on the card is a multiple of both 6 and 8?

Question

Mathematics

Logan Hoover

26 December, 11:02

A set of 48 cards is numbered with positive integers from 1 to 48.

If the cards are shuffled and one is chosen at random, what is the probability that the number on the card is a multiple of both 6 and 8?

+5

Answers (2)

Know the Answer?

Zoie Shaffer · Answer 1

Multiples of 6 and 8 for numbers - 1 - 14 are:-

48, 24

so the answer is 2/48 = 1/24.

Kaylee · Answer 2

multiples of 6 = 6, 12, 18, 24, 30, 36,42, 48

multiples of 8 = 8, 16, 24,32,40,48

24 & 48 are the common multiples

so there is a 2 out of 48 chance which is 2/48 which reduces to 1/24 probability

A set of 48 cards is numbered with positive integers from 1 to 48.If the cards are shuffled and one is chosen at random, what is the probability that the number on the card is a multiple of both 6 and 8?

A set of 48 cards is numbered with positive integers from 1 to 48.

If the cards are shuffled and one is chosen at random, what is the probability that the number on the card is a multiple of both 6 and 8?