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26 December, 08:50

Given f (x) = x^3+4x^2+5x+2 and that - 1 is a zero of f (x). What is the factor of f (x)

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  1. 26 December, 09:43
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    From the context, the question is asking "What are the factors of f (x) ".

    As Sxerks indicated in the comments, (x-1) is a root = > (x+1) is a factor.

    To factor completely, a long division or synthetic division can be done to find

    f (x) / (x+1) = (x^3+4x^2+5x+2) / (x+1) = x^2+3x+2 with no remainder.

    Factor the resulting quadratic,

    x^2+3x+2 = (x+2) (x+1)

    factors f (x) completely into

    f (x) = (x+1) ^2 (x+2)
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