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5 March, 14:34

What are the roots of the polynomial x^3-7x=6x-12

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  1. 5 March, 15:15
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    To solve the exercise shown above, you must follow the proccedure shown below:

    1. You have the following polynomial:

    x ³ - 7x=6x-12

    2. When you factor it, you obtain the following expression:

    (x-3) (x-1) (x+4) = 0

    3. Therefore, you have that the roots of the polynomial are:

    x1=-4

    x2=1

    x3=3
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