4 times the lesser of two consecutive even integers is 12 less than twice the greater number. find the integers

Let the two consecutive even integers be 2n + 2n + 2.

4 times the lesser of the two integers is 12 less than twice the greater number. Therefore

4 (2n) = 2 (2n + 2) - 12

8n = 4n + 4 - 12

4n = - 8

n = - 2

Therefore

2n = - 4

2n + 2 = - 2

Answer:

The integers are - 4 and - 2.