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1 May, 16:15

Anna went from home to school with the speed 3 km/hour. She ran back home with the speed 6 km/hour. Her sister Olga went to school and back with the same speed, and she spent as much time on the road as Anna. What was Olga's speed?

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  1. 1 May, 17:54
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    Let:

    v = Olga's speed

    t = the time Anna spent going to school (3 km/hour)

    t/2 = the time Anna spent running back home with speed of 6 km/hour

    So, t + t/2 = 3t/2 is the total time

    In the meantime distance = speed*time and the both made the same distance we can put it as:

    3t + 6 * (t/2) = (3t/2) * v

    6t = (3/2) tv divide both sides by t

    (3/2) v = 6

    v = 2*6/3

    v = 4 km/hour

    Olga's speed was 4 km/hour.
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