Question 1:

y=5^4x-3 what is the ordered pair? (its 5 to the power of 4)

question 2:

which ordered pair makes the equation true?

2y=-5x-4

a. (-2,3)

b. (1,-4)

c. (0,2)

d. (-1,1)

Question 1:

I'm actually not sure which term you ment exactly, so I calculated the solution for three possible variations of your term, depending on how one sets the brackets.

To calculate an ordered pay just set x or y to some value, insert it into the equation and you get the solution for the other variable.

In these calculations I always picked x so values would get eliminated or as close to 0 as possible to make it easier.

variation 1 of term:

y = (5^4) * (x-3)

insert x=3

y = (5^4) * (3-3) = = (5^4) * 0=0

pair: (3,0)

variation 2 of term:

y = (5^4) * x-3

insert x=0:

y = (5^4) * 0-3=0-3=-3

pair: (0,-3)

variation 3 of term:

y=5^ (4*x-3)

insert x=1:

y=5^ (4*1-3) = 5^1=5

pair: (1,5)

question 2:

2y=-5x-4

just insert the pairs as (x, y) into the equation:

a. (-2,3)

2*3=-5*-2-4

6=10-4 yes

b. (1,-4)

2*-4=-5*1-4

-8=-9 no

c. (0,2)

2*2=-5*0-4

4=-4 no

d. (-1,1)

2*1=-5*-1-4

2=5-4 no