Solve the inequality. |2k + 1| ≥ 5

If you remove the absolute value of |2k+1| ≥ 5, you will get:

a) 2k+1 ≥ 5 and b) 2k+1≤ - 5. (for the negative, you flip the inequality sign)

Hence

a) 2k+1 ≥ 52 → k≥5-1 and k≥ 2 And

b) 2k+1 ≤ - 5 → k≤ - 5 - 1 and k ≤ - 3

Then - 3 ≥ k ≥ 2