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23 October, 08:58

We have f ' (x) = 6x2 + 6x - 432, so f '' (x) = 12x+6 correct: your answer is correct., which equals 0 when

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  1. 23 October, 10:40
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    The derivative of the first derivative given to be, f' (x) = 6x² + 6x - 432 is given to be,

    f'' (x) = 12x + 6

    As asked in the given, the value of the second derivative becomes zero when the value of x is,

    f" (x) = 0 = 12x + 6

    12x + 6 = 0

    Subtract 6 from both sides of the equation such that,

    12x = - 6

    Divide both sides of the equation by 12 giving us an answer of

    x = - 1/2.

    Hence, x = - 1/2.
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