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23 April, 04:44

Identify the 19th term of the arithmetic sequence 5, 16, 27 ...

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Answers (2)
  1. 23 April, 06:16
    0
    This sequence is represented as:

    a (n+1) = 5 + 11n

    So for 19th term, a (19) = 5 + 11 * (19-1) = 203
  2. 23 April, 06:49
    0
    An = a1 + (n - 1) (d)

    where a1 is the first term and d is the common difference.

    a19 = 5 + (19 - 1) (11)

    a19 = 5 + (18) (11)

    a19 = 5 + 198

    a19 = 203
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