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10 March, 04:04

The length of rectangle is 2 yd longer than its width. The perimeter of the rectangle is 32 yd, find its area

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  1. 10 March, 07:38
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    The length of a rectangle is 2yd longer than it's width. If the permitter is 32yd find it's area.

    Let width be x

    Length = x+2 yards

    Perimeter = 2 * (l+w)

    = 2 * (x+2+x)

    =2 * (2x+2)

    =4x+4

    4x+4 = 32

    4x=32-4

    4x=28

    x=7 = width

    length = 9
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