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17 February, 13:40

One number is five more than twice another. If their sum is decreased by ten, the result is twenty-two. Find the numbers.

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Answers (2)
  1. 17 February, 13:59
    0
    X = 2y + 5

    (x + 2y + 5) - 10 = 22

    (2y + 5 + 2y + 5) = 4y + 10

    (4y + 10) - 10 = 22

    4y = 22 y = 5.5

    x = 2 (5.5) + 5 x = 16

    x = 16 y = 5.5
  2. 17 February, 14:02
    0
    (x+2x+5) - 10=22

    3x+5=32

    3x=27

    x=9

    So, the numbers are 3 and 11
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