1. The length of a rectangle is 7 mm longer than its

width. Its perimeter is more than 62 mm. Let w equal the width of the rectangle.

Question

Mathematics

Brady Ibarra

29 December, 07:41

1. The length of a rectangle is 7 mm longer than its

width. Its perimeter is more than 62 mm. Let w equal the width of the rectangle.

+3

Answers (2)

Know the Answer?

Jovani Daniels · Answer 1

L=w+7

p>62

2l+2w=p

2w+14+2w=p

4w+14=p

4w=p-14

w=1/4p-3.5

Edgar Erickson · Answer 2

W is greater than 12

You can figure this out because you know that the length is w + 7 and the width is w. Now you need to multiply by 2 to find the perimeter. So your equation will be

w+w+w+w+7+7 is greater than 62. You can simplify this equation into 4w + 14 is greater than 62. To find the width, you need to subtract 14 from both sides of the equation and you end up with 4w is greater than 48. Now to isolate the variable (w) you need to divide both sides by 4 which will give you w is greater than 12. It cannot be equal to 12 because then the perimeter will have to be 62 and it cannot be less than 12 because the problem is saying that the perimeter is more than 62.

1. The length of a rectangle is 7 mm longer than itswidth. Its perimeter is more than 62 mm. Let w equal the width of the rectangle.

1. The length of a rectangle is 7 mm longer than its

width. Its perimeter is more than 62 mm. Let w equal the width of the rectangle.