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24 March, 18:05

How do I solve this system using substitution: y = x - 7; 2x + y = 8

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  1. 24 March, 21:54
    0
    Y=x-7

    2x+y=8

    2x+x-7=8

    3x=15

    x=15/3

    x=5

    y=x-7

    y=5-7

    y=-2

    x=5

    y=-2
  2. 24 March, 22:03
    0
    Y = x - 7

    2x + y = 8

    2x + (x - 7) = 8

    2x + x - 7 = 8

    3x - 7 = 8

    + 7 + 7

    3x = 15

    3 3

    x = 5

    y = x - 7

    y = 5 - 7

    y = - 2

    (x, y) = (5, - 2)
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