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21 December, 05:27

Phyllis solved the compound inequality 16 < 2 (3x - 1) < 28. She began by first breaking the inequality into two separate inequalities, then she correctly solved each for x. 16 < 2 (3x - 1) and 2 (3x - 1) < 28 3 < x x < 5 Which graph represents her solution?

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  1. 21 December, 06:18
    0
    16<2 (3x-1) <28 divide all terms by 2

    8<3x-1<14 add 1 to all terms

    9<3x<15 divide all terms by 3

    3
    x = (3,5) in interval notation

    On a number line, it would be a line segment from 3 to 5 with open circles at 3 and 5.

    On a coordinate system graph, it would be an infinitely high shaded plane between the vertical lines x=3 and x=5
  2. 21 December, 07:41
    0
    From question,

    16<2 (3x-1) = 16<6x-2

    =16+2<6x-2+2

    =18<6x

    =18/6<6x/6

    =3
    Again,

    2 (3x-1) <28

    =6x-2<28

    =6x-2+2<28+2

    =6x<30

    =6x/6<30/6

    =x<5

    So both of ther graphs 3
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