It is now 10:29

a. m., but when the bell rings at 10:30

a. m. suzette will be late for french class for the third time this week. she must get from one side of the school to the other by hurrying down three different hallways. she runs down the first hallway, a distance of 35.0 m, at a speed of 3.50 m/s. the second hallway is filled with students, and she covers its 48.0 m length at an average speed of 1.20 m/s. the final hallway is empty, and suzette sprints its 60.0 m length at a speed of 5.00 m/s.

Question

Mathematics

Guest

27 July, 08:21

It is now 10:29

a. m., but when the bell rings at 10:30

a. m. suzette will be late for french class for the third time this week. she must get from one side of the school to the other by hurrying down three different hallways. she runs down the first hallway, a distance of 35.0 m, at a speed of 3.50 m/s. the second hallway is filled with students, and she covers its 48.0 m length at an average speed of 1.20 m/s. the final hallway is empty, and suzette sprints its 60.0 m length at a speed of 5.00 m/s.

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Answers (1)

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Chump · Answer 1

If the question here is Suzette late? Then the answer is:

First hallway: change in t = change in d / v = 35.0 m / 3.50 m/s = 10.0s

Second hallway: change in t = change in d / v = 48.0 m / 1.20 m/s = 40.0 s

Third hallway: change in t = change in d / v=60.0 m / 5.00 m/s = 12.0s

=10.0s + 40.0s + 12.0s = 62.0s

This is 2 s after the bell rings so, Suzette is late again for the third time.