Find the probability that 4 randomly selected people all have the same birthday. Ignore leap years. Round to eight decimal places.

The number of days of not leap years is 365.

So, the number of different variations of birthdays for 4 people is 365 * 365 * 365 * 365 = (365) ^4

The probability that all of them be one specific day is 365 / (365) ^4 = 1 / (365) ^3 ≈ 0.00000002.

Answer: 0.00000002