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1 June, 21:23

Find the probability that 4 randomly selected people all have the same birthday. Ignore leap years. Round to eight decimal places.

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  1. 2 June, 00:17
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    The number of days of not leap years is 365.

    So, the number of different variations of birthdays for 4 people is 365 * 365 * 365 * 365 = (365) ^4

    The probability that all of them be one specific day is 365 / (365) ^4 = 1 / (365) ^3 ≈ 0.00000002.

    Answer: 0.00000002
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