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9 October, 17:51

Factors of 3x^2y^2+6x^2+12y^2+24

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  1. 9 October, 18:02
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    Look for the GCF

    GCF = 3

    so we have

    3 (x^2y^2 + 2x^2 + 4y^2 + 8) Factor by grouping:-

    = 3[ x^2 (y^2 + 2) + 4 (y^2 + 2) ]

    = 3 (x^2 + 4) (y^2 + 2)
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