Solving for inequalities

8p-13 <-2+7p and 20+4p< 2p+14?

8p-13<-2+7p and 20+4p<2p+14

8p-13<-2+7p

8p-13<7p-2 (Simplify both sides of the inequality)

8p-13-7p<7p-2-7p (Subtract 7p from both sides)

p-13<-2

p-13+13<-2+13 (Add 13 to both sides)

p<11

20+4p<2p+14

4p+20<2p+14 (Simplify both sides of the inequality)

4p+20-2p<2p+14-2p (Subtract 2p from both sides)

2p+20<14

2p+20-20<14-20 (Subtract 20 from both sides)

2p<-6

2p/2 < - 6/2 (Divide both sides by 2)

p<-3

So the answer to your question is:

P <11 and P < - 3