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7 October, 08:15

Solve 6 over x minus 6 equals the quantity of x over x minus 6, minus six halves. for x, and determine if the solution is extraneous or not.

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  1. 7 October, 10:31
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    6 / (x - 6) = x / (x - 6) - 6/2

    6 / (x - 6) = x / (x - 6) - 3

    6 = x - 3 (x - 6)

    6 = x - 3x + 18

    -12 = - 2x

    x = 6

    However, substituting x = 6 makes the denominator equal to zero, the this is an extraneous solution.
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