A ball is thrown from a height of 130 feet with an initial downward velocity of 6/fts. The ball's height h (in feet) after t seconds is given by the following.

h = 130-6t-16t^2 How long after the ball is thrown does it hit the ground? Round your answer (s) to the nearest hundredth.

t = __ sec

Question

Carleigh Gill

24 June, 15:36

+1

Answers (1)

Know the Answer?

Daniela Brennan · Answer 1

Plug in numbers until you get the right answer. And the equation should be h=-16t^2-6t+130. It's between 2 and 3

A ball is thrown from a height of 130 feet with an initial downward velocity of 6/fts. The ball's height h (in feet) after t seconds is given by the following.h = 130-6t-16t^2 How long after the ball is thrown does it hit the ground? Round your answer (s) to the nearest hundredth.t = __ sec