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24 June, 15:36

A ball is thrown from a height of 130 feet with an initial downward velocity of 6/fts. The ball's height h (in feet) after t seconds is given by the following.

h = 130-6t-16t^2 How long after the ball is thrown does it hit the ground? Round your answer (s) to the nearest hundredth.

t = __ sec

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  1. 24 June, 17:44
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    Plug in numbers until you get the right answer. And the equation should be h=-16t^2-6t+130. It's between 2 and 3
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