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30 March, 03:07

Find the half-life of an element which decays by 3.411% each day. Hint: use y = ab^t.

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  1. 30 March, 04:55
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    A/2=a ((100-3.411) / 100) ^t

    a/2=a (0.96589) ^t

    0.5=0.96589^t

    ln (0.5) = t (ln (0.96589))

    t=ln (0.5) / ln (0.96589)

    t≈19.97 days (to nearest hundredth of a day)
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