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12 April, 12:00

A test consists of 20 problems and students are told to answer any 15 of these questions. In how many different ways can they choose the 15 questions?

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  1. 12 April, 12:45
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    Since order is not important, we are looking for unique combinations. For this type of problem you use the "n choose k" equation.

    n! / (k! (n-k) !), where n=total amount of choices, k=number of choices made.

    In this case:

    20! / (15! (20-15) !)

    20! / (15!*5!)

    15504
  2. 12 April, 14:53
    0
    1 - 15

    2 - 17

    3 - 18

    4 - 19

    5 - 20
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