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2 April, 08:37

Tan [x-pi/4] = tanx - 1

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  1. 2 April, 08:57
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    Solve for x:

    -tan (π/4 - x) = tan (x) - 1

    Subtract tan (x) - 1 from both sides:

    1 - tan (π/4 - x) - tan (x) = 0

    Simplify and substitute y = - tan (x).

    1 - tan (π/4 - x) - tan (x) = (-tan (x) (1 - tan (x))) / (-tan (x) - 1)

    = (y (y + 1)) / (y - 1):

    (y (y + 1)) / (y - 1) = 0

    Multiply both sides by y - 1:

    y (y + 1) = 0

    Split into two equations:

    y = 0 or y + 1 = 0

    Substitute back for y = - tan (x):

    -tan (x) = 0 or y + 1 = 0

    Multiply both sides by - 1:

    tan (x) = 0 or y + 1 = 0

    Take the inverse tangent of both sides:

    x = π n_1 for n_1 element Z

    or y + 1 = 0

    Subtract 1 from both sides:

    x = π n_1 for n_1 element Z

    or y = - 1

    Substitute back for y = - tan (x):

    x = π n_1 for n_1 element Z

    or - tan (x) = - 1

    Multiply both sides by - 1:

    x = π n_1 for n_1 element Z

    or tan (x) = 1

    Take the inverse tangent of both sides:

    Answer: x = π n_1 for n_1 element Z or x = π n_2 + π/4 for n_2 element Z
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