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16 February, 20:50

The length of a rectangle is four times its width.

If the area of the rectangle is 144 yd^2, find its perimeter.

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  1. 17 February, 00:33
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    Hello;

    x is the length, y the width:

    x = 4y ... (1)

    xy = 144 ... (2)

    subsct in (2) : 4y (y) = 144

    y² = 36

    y = 6 yd so : x = 24 yd

    the perimeter is : 2 (6+24) = 60 yd
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