Joseph spent $76.82 at the pet food store. He paid $47.54 for a bag of dog food and $2.44 each for some treats.

How many treats did he purchase? (just wanna know)

This is the concept of algebra;

let the number of treats be x;

Total amount spent = (cost of dog food) + (cost of treaties)

Total cost=$76.82

Cost of dog food=$47.54

Total cost of treaties given that each cost $ 2.44 will be:

2.44*x=2.44x

therefore:

76.82=47.54+2.44x

2.44x=76.82-47.54

2.44x=29.28

x=29.28/2.44

x=12

therefore there were 12 treats

To find the answer first subtract $47.54 from the total (76.82-47.54 = 29.28) Then divide the remaining money, 29.28 by the cost of one dog treat, $2.44. 29.28/2.44 = 12. Joseph purchased 12 dog treats. 12 times 2.44 is 29.28, plus the bag of dog food is 47.54, which totals 76.82.