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3 February, 19:00

How many 2 digit whole numbers are increased by 18 when they're digits are reversed

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  1. 3 February, 20:44
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    This can be calculated easily.

    As any two digit number can be written in the following form:

    N = 10x + y

    If we reverse the number now, it would become:

    N' = 10y + x

    So if we subtract one from the other, we should obtain 18 (as mentioned in the question).

    N-N' = 18

    => x-y = 2

    Thus, any number whose digits differ by two would be an aswer to the question.

    The only numbers which satisfy this are : 13,24,35,46,57,68,79

    But this would not be true for any 3 or more digit number.
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