Ask Question
15 April, 21:39

Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104.

+4
Answers (2)
  1. 16 April, 00:12
    0
    If we divide the 7th term by the third it gives us r^4 (common ratio to power 4).

    r^4 = 7104/444 = 16

    so r = 4th root of 16 = 2

    So 6th term will be the 7th term / 2 = 7104 / 2 = 3552
  2. 16 April, 00:21
    0
    Given the value of t3 and t7, and t7 = t3 * r^4, where r represents the geometric quotient.

    So 7104 = 444 * r^4 - > solve for r, you will get r = 2 or - 2

    So, for r = 2, t6 = t7 / r = 7104 / 2 = 3552

    For r = - 2, t6 = - 3552
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers