The sum of 5 consecutive integers is 120. What is the third number in this sequence?

Ok so

x - the smallest

The other 4 are : x+1, x+2, x+3, x+4

We know that sum is 120

So

x+x+1+x+2+x+3+x+4=120

Combine like terms

5x+10=120

Subtract 10 on both sides

5x=120-10

5x=110

Divide by 5 on both sides

X=22

The third number is x+2 = 22+2=24

The integer is 24 so the third number is 72