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8 September, 09:30

The length of a rectangle is 8 inches more than the width. The perimeter is 32 inches. Find the length and width of the rectangle

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Answers (2)
  1. 8 September, 09:49
    0
    P = 2 (L + W)

    P = 32

    L = W + 8

    32 = 2 (W + 8 + W)

    32 = 2 (2W + 8)

    32 = 4W + 16

    32 - 16 = 4W

    16 = 4W

    16/4 = W

    4 = W < = = = width is 4 inches

    L = W + 8

    L = 4 + 8

    L = 12 < = = = length is 12 inches
  2. 8 September, 12:47
    0
    W = 4, l = 12

    First, write down what you know.

    l = w + 8

    2l + 2w = 32

    Now substitute (w+8) for l in the 2nd equation.

    2 (w+8) + 2w = 32

    Distribute the 2

    2w + 16 + 2w = 32

    Subtract 16 from both sides

    2w + 2w = 16

    Combine the w terms

    4w = 16

    Divide both sides by 4

    w = 4

    Now using the l = w+8 expression, substitute the known value for w

    l = 4 + 8

    l = 12

    So w = 4, and l = 12
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